craccon CTF 2025 (Short Writeups)
Brief descriptions and short writeups for the challenges I solved in craccon-ctf 2025.
1. PowerPlay
As AES encryption is being used and it has the underlying SBOX implementation with data leakage being there we can do a sidechannel attack. I also referred to some writeups like https://github.com/emorchy/PicoCTF2023-PowerAnalysis that also used side channel attacks but in a different scenario. Specifically, I did CPA (http://wiki.newae.com/Correlation_Power_Analysis) and asked ChatGPT to write a quick script for me that implemented this method.
import numpy as np
from pathlib import Path
import re
# ---------- Load data ----------
PT_PATH = Path('plaintexts.npy') # shape (N, 16), dtype=uint8
TR_PATH = Path('power_traces.npy') # shape (N, T), dtype=float32/float64
ENC_PATH = Path('enc.py') # contains ciphertext hex as a comment
plain = np.load(PT_PATH) # (N,16) uint8
traces = np.load(TR_PATH) # (N,T) float
N, T = traces.shape
assert plain.shape == (N, 16)
# ---------- AES S-box + Hamming Weight ----------
SBOX = np.array([
0x63,0x7c,0x77,0x7b,0xf2,0x6b,0x6f,0xc5,0x30,0x01,0x67,0x2b,0xfe,0xd7,0xab,0x76,
0xca,0x82,0xc9,0x7d,0xfa,0x59,0x47,0xf0,0xad,0xd4,0xa2,0xaf,0x9c,0xa4,0x72,0xc0,
0xb7,0xfd,0x93,0x26,0x36,0x3f,0xf7,0xcc,0x34,0xa5,0xe5,0xf1,0x71,0xd8,0x31,0x15,
0x04,0xc7,0x23,0xc3,0x18,0x96,0x05,0x9a,0x07,0x12,0x80,0xe2,0xeb,0x27,0xb2,0x75,
0x09,0x83,0x2c,0x1a,0x1b,0x6e,0x5a,0xa0,0x52,0x3b,0xd6,0xb3,0x29,0xe3,0x2f,0x84,
0x53,0xd1,0x00,0xed,0x20,0xfc,0xb1,0x5b,0x6a,0xcb,0xbe,0x39,0x4a,0x4c,0x58,0xcf,
0xd0,0xef,0xaa,0xfb,0x43,0x4d,0x33,0x85,0x45,0xf9,0x02,0x7f,0x50,0x3c,0x9f,0xa8,
0x51,0xa3,0x40,0x8f,0x92,0x9d,0x38,0xf5,0xbc,0xb6,0xda,0x21,0x10,0xff,0xf3,0xd2,
0xcd,0x0c,0x13,0xec,0x5f,0x97,0x44,0x17,0xc4,0xa7,0x7e,0x3d,0x64,0x5d,0x19,0x73,
0x60,0x81,0x4f,0xdc,0x22,0x2a,0x90,0x88,0x46,0xee,0xb8,0x14,0xde,0x5e,0x0b,0xdb,
0xe0,0x32,0x3a,0x0a,0x49,0x06,0x24,0x5c,0xc2,0xd3,0xac,0x62,0x91,0x95,0xe4,0x79,
0xe7,0xc8,0x37,0x6d,0x8d,0xd5,0x4e,0xa9,0x6c,0x56,0xf4,0xea,0x65,0x7a,0xae,0x08,
0xba,0x78,0x25,0x2e,0x1c,0xa6,0xb4,0xc6,0xe8,0xdd,0x74,0x1f,0x4b,0xbd,0x8b,0x8a,
0x70,0x3e,0xb5,0x66,0x48,0x03,0xf6,0x0e,0x61,0x35,0x57,0xb9,0x86,0xc1,0x1d,0x9e,
0xe1,0xf8,0x98,0x11,0x69,0xd9,0x8e,0x94,0x9b,0x1e,0x87,0xe9,0xce,0x55,0x28,0xdf,
0x8c,0xa1,0x89,0x0d,0xbf,0xe6,0x42,0x68,0x41,0x99,0x2d,0x0f,0xb0,0x54,0xbb,0x16
], dtype=np.uint8)
HW = np.array([bin(i).count("1") for i in range(256)], dtype=np.uint8)
# ---------- Normalize traces (per time sample) ----------
traces_z = (traces - traces.mean(axis=0)) / (traces.std(axis=0) + 1e-9)
# ---------- CPA core ----------
def cpa_byte(byte_idx: int):
"""Return (best_guess, best_abs_corr, best_time_index) for one key byte."""
p = plain[:, byte_idx] # (N,)
guesses = np.arange(256, dtype=np.uint8) # (256,)
# Model matrix: rows=guesses, cols=samples -> shape (256, N)
m = HW[SBOX[np.bitwise_xor(p[:, None], guesses[None, :])]].T.astype(np.float32)
# Standardize each row
m -= m.mean(axis=1, keepdims=True)
m /= (m.std(axis=1, keepdims=True) + 1e-6)
# Correlate: (256 x N) @ (N x T) -> (256 x T). Since standardized, this is Pearson ρ.
corr = (m @ traces_z) / (len(p) - 1)
abs_corr = np.abs(corr)
g_idx, t_idx = np.unravel_index(np.argmax(abs_corr), abs_corr.shape)
return int(g_idx), float(abs_corr[g_idx, t_idx]), int(t_idx)
key_bytes = []
byte_corrs = []
byte_times = []
for b in range(16):
g, c, t = cpa_byte(b)
key_bytes.append(g)
byte_corrs.append(c)
byte_times.append(t)
key = bytes(key_bytes)
key_hex = key.hex()
print("Recovered AES-128 key:", key_hex)
print("Per-byte best |corr|:", [round(c, 3) for c in byte_corrs])
print("Per-byte time indices:", byte_times)
# ---------- Decrypt ciphertext from enc.py (if present) ----------
try:
enc_text = ENC_PATH.read_text()
# Look for a long hex string after a '#'
m = re.search(r"#\s*([0-9a-fA-F]{64,})", enc_text)
if m:
ct_hex = m.group(1).strip()
from Crypto.Cipher import AES
from Crypto.Util.Padding import unpad
cipher = AES.new(key, AES.MODE_ECB)
pt_padded = cipher.decrypt(bytes.fromhex(ct_hex))
try:
pt = unpad(pt_padded, 16)
print("Decrypted plaintext:", pt)
except ValueError:
print("Decrypted (raw, unpad failed):", pt_padded)
else:
print("Ciphertext not found in enc.py comment. Skipping decryption.")
except FileNotFoundError:
print("enc.py not found. Skipping decryption.")
2. Fake Estate
The alert in the challenge said that "The Man In the Middle" stopped us from accessing the desired endpoint. This reminded me of the Next.js middleware bypass CVE. So I just had to attach the following header while making a request:
x-middleware-subrequest: src/middleware:src/middleware:src/middleware:src/middleware:src/middleware3. Pay2Win
Looking at the image given to us and the description of the challenge it was clear that pixelation was being used to hide the data, but I had no idea which tool to use or how it works. Checking the metadata and strings of the image revealed greenshot. Then I found this Depixelization_poc which clearly stated how to remove this blurring from greenshot. Cropping the image and running the tool gave the password for the admin panel. After logging in to it, I inspected the source code and inside it found the hidden flag.
Now starts the favourite part of CTFS for me forensics and cloud.
4. Snapshot
It was a memdump provided to us so I opened it with volatility and explored it. First I ran some basic commands like windows.info, windows.pslist... but they did not reveal anything very interesting, I thought of pursuing the open StikyNot.exe but was too lazy. So I then did filescan and got:
0x1e5e9800 \Windows\System32\zh-CN\httpflag.ctf.defhawk.com8000flagsnapshotI then tried accessing http://flag.ctf.defhawk.com:8000/flag/ but it asked for x-api-key so I just ran strings through snapshot and found it: x-api-key: sn4psh0t_v0l4t1litty then I got flag.
5. To The Vault
I first proceeded the standard way and visited https://azurectflab1.blob.core.windows.net/$web?restype=container&comp=list. This gave a list of files which I went through several times but did not get anything, so I opened Microsoft Azure Storage Explorer from where I changed the visibility settings to All Blobs and got to see the hidden creds.txt file.
I then logged in the Azure CLI with these credentials and ran az keyvault list -o table which gave name of the vault as ctflab1. Then I ran a simple script to fetch all secret values which gave flag.
for s in $(az keyvault secret list --vault-name ctflab1 --query "[].name" -o tsv); do
echo "== $s =="
az keyvault secret show --vault-name ctflab1 --name "$s" --query value -o tsv
done6. The Hidden Snap
It was interesting as I first got something unintended 🥲 and they patched it. I asked ChatGPT about the most commonly used places to store hidden files on a local filesystem and after few commands I got a hit on the path cat /root/.hidden_snap_id and snap-0e37d8eae0553406e . I realised this is a public snapshot id for AWS because I had solved a similar challenge before from BSides Mumbai. I ran an automated script for all regions and got a hit in the ap-south-1 region.
aws ec2 describe-snapshots --snapshot-ids snap-0e37d8eae0553406e --region ap-south-1I then created a volume from this snapshot, launched an EC2 instance and attached this volume. After this, I ssh into the instance, mounted xvdf1 and explored it till I found the flag.
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